In my previous post, I showed a simple vacuum fluorescent display filament driver built using a 555 timer and a custom hand-wound, center-tapped toroidal pulse transformer. And as promised in my earlier comment, I am going to show you the remainder of the VFD driving circuit here.

As I mentioned before, there are many driver chips (e.g. MAX6921, MAX6931) readily available for interfacing with VFDs. The driver circuit I am showing here is a bit more complex as it uses only the generic 74HC’s and discrete transistors.

The basic technique for driving a multiplexed VFD is very similar to that for driving a 7-segment LED display. The major difference is the voltage requirement for the control gates and segment. For a VFD, the driving voltage is typically between 20V and 30V instead of the TTL or CMOS logic level used for driving 7-segment LED displays. Thus we must employee some kind of voltage shifting circuitry to translate the logic level signal into the voltage required by the VFD.

Here is the schematic of the VFD driver circuit I built:

VFD Driver Circuit
VFD Driver Circuit

In this schematic, IC5 and IC6 are two 74HC138 3-8 line decoders, they are chained together to generate the strobe signal needed for driving the gate. a couple of 74HC04 inverter chips are used to invert the outputs from 74HC138’s so that the input sequence to the 3-8 line decoders corresponds directly to the grid that is being driven high. Of course, the inverters are not strictly necessary as you could easily invert the control signals in software.

IC7 and IC8 are two 74HC595 shift registers, their outputs are used to drive the nine segments (i.e. a-g, comma and decimal point).

The TTL outputs from IC5-IC8 are translated to higher driving voltages required by the VFD via four ULN2003A darlington driver chips. The output signals from the ULN2003A’s are then inverted by the PNP transistors (all of which are 2N3906). Each PNP transistor controls a control grid or a display segment. Technically speaking, using ULN2003A is a bit of an overkill as the load current is negligible in this case. You could easily achieve the same result by replacing the darlington driver chips with individual NPN transistors such as 2N3904. But using ULN2003A does simplify the circuit a little bit as the base resistors are included on the chip.

Because the current requirement for driving the gates and segments is very low for vacuum fluorescent displays, we can use relatively large load and base resistors. The values of these resistors are not critical and can range from 100K to 1M. Typically, we want to choose larger resistors to limit current consumption. But on the flip side, large resistance value does have some negative impact on signal transition time (e.g. rise time) due to the effect of the large RC constants formed with respect to the BJT junction capacitance. When the refresh rate is relatively low (50Hz to 100Hz), this RC constant has little effect on the quality of the driving signal. But as the refresh rate increases, the RC constant’s effect on the signal slew rate will become more pronounced and causing noticeable ghosting effect. Of course, this issue can be easily addressed by using a complementary output stage, but the resulting circuit will become much more complex and you may as well just use a dedicated driver chip at that point.

Here are a couple of pictures of the driver circuit I built on a perfboard:

VFD Driver 2
VFD Driver 2
VFD Driver 3
VFD Driver 3

And here is a picture showing the wired-up VFD. The VFD I salvaged was connected to a small PCB. I decided keep part of the PCB and used it as a breakout board for the pins.

VFD Driver 1
VFD Driver 1

To drive the VFD, a strobe signal (generated via the two 74HC138’s) is needed to assert each of the control grid and while the grid is asserted the corresponding segments to be displayed are driven high. The following oscilloscope capture shows the gate waveforms of two adjacent digits. The gate waveforms are also illustrated in the schematic above. To prevent two adjacent VFD segments being addressed at the same time due to degraded slew rate mentioned earlier, there should be some delays between adjacent pulses. A few microseconds is usually sufficient.

Grid Drive Waveform
Grid Drive Waveform

This circuit can be used to interface with a microcontroller directly. To test it out, I used an Arduino to generate the following display sequences (code included at the end). The picture on the left shows what the display looks like without a filter, and the image on the right shows the same display with a blue filter. As you can see even without a filter, the numbers displayed on the VFD are pretty clear:

Display (without filter)
Display (without filter)
Display (with filter)
Display (with filter)

Here is the simple test program I used to generate the numbers displayed above. Note that only the first 12 digits are used and the last segment is purposely left blank.

#include <Arduino.h>

const int NUM_OF_GRIDS = 13;
const int PIN_B0 = 2;
const int PIN_B1 = 3;
const int PIN_B2 = 4;
const int PIN_B3 = 5;

const int PIN_DS = 6;
const int PIN_OE = 7;
const int PIN_LATCH = 8;
const int PIN_CLK = 9;

const int DIGITS[]={63, 6, 91, 79, 102, 109, 125, 7, 127, 111, 63};
const int DASH = 64;
const int DOT = 128;
const int COMMA = 256;

int gridCounter = 0;
int b = 1;

void setup()
    for (int i = 2; i<=9; i++) pinMode(i, OUTPUT);

void loop()
    //generate pulse to drive each grid 
    digitalWrite(PIN_B0, gridCounter & 1);
    digitalWrite(PIN_B1, (gridCounter & 2) >> 1);
    digitalWrite(PIN_B2, (gridCounter & 4) >> 2);
    digitalWrite(PIN_B3, (gridCounter & 8) >> 3);
    digitalWrite(PIN_OE, LOW);

    if (gridCounter % NUM_OF_GRIDS < 10) {
        b = DIGITS[gridCounter];
    } else {
        if (gridCounter == NUM_OF_GRIDS - 1) {
            b = 0; //skip the last segment
        } else {
            b = DIGITS[gridCounter - 10];
    //displays DIGITS[gridCounter]
    digitalWrite(PIN_LATCH, LOW);
    shiftOut(PIN_DS, PIN_CLK, MSBFIRST, b >> 8);
    shiftOut(PIN_DS, PIN_CLK, MSBFIRST, b);
    digitalWrite(PIN_LATCH, HIGH);
    //clears current digit to prevent ghosting
    digitalWrite(PIN_LATCH, LOW);
    shiftOut(PIN_DS, PIN_CLK, MSBFIRST, 0);
    shiftOut(PIN_DS, PIN_CLK, MSBFIRST, 0);
    digitalWrite(PIN_LATCH, HIGH);
    digitalWrite(PIN_OE, HIGH);
    digitalWrite(PIN_B0, LOW);
    digitalWrite(PIN_B1, LOW);
    digitalWrite(PIN_B2, LOW);
    digitalWrite(PIN_B3, LOW);  

    if (gridCounter >= NUM_OF_GRIDS) gridCounter = 0;
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10 Thoughts on “A DIY Vacuum Fluorescent Display Driver”

  • Nice project, I was looking into something similar as I’m using VFD displays in my current project too.
    Why not use the 74*238 which has active-high outputs and do away with the inverters? Why not use a proper BCD to 7-segment decoder instead of the 74*595 hack? You could’ve then focused on the output stage :-)

    • Thanks Radu,

      Well, of course you could use a BCD to 7-segment chip. I didn’t have any. Also, I wanted to drive the two extra segments (the comma and dot) and typical decoders (e.g. CD4511) does not have the extra segments built-in.

  • i am curious, couldn’t you have gotten away with only the PNP transistors, directly driven by the shift registers(or hex inverters, if you are so keen on using them)?

    • The output voltage from the TTL inverter is not high enough to turn those PNP transistors off. Since the VFD grid voltage is relatively high (around 27V in my case), you can’t use a CMOS inverter (e.g. CD4069) either.

  • I am trying to drive some IV-11 VFD tubes for a clock. These are being driven statically (not Multiplexed). The anode voltages are 25 volts DC and the grids are tied high since the operation of them is on at all times. I want to use 74ls247 which are BCD to 7 segment decoder/drivers. What type of transistor or ULN2003a must I use to make these work? Can you help me out?

    I am not an engineer but just a hobbyist who like to build clocks.

  • Kerry,

    Good morning. Thanks for the circuit to switch the anode voltages of 25 volts. Can I use 2N3904 and 2N3906 transistors for this circuit? Can I feed the inputs from an LS247 decoder driver (open collector outputs)? If so dont I really need a base resistor and a pullup resistor on the base to insure that they switch on and off properly?

    • Hi Ed,

      Yes, you don’t necessarily need the Darlington driver and you certainly can use a 2n3904 in its place for each channel and use it to translate the output voltage from 74LS247 to drive the 2n3906 for the VFD grid.

  • Hi kwong! I have a Display similar to your (DISPLAY ITRON FG1013/ RS1) and I would like to put the photo here but I do not know.
    My display has 10 digits but the name of the pins that is marked on the pcb is the following:
    Pins 1-11: a, b, c, d, e, P, f, g, dot, down arrow, -VF.
    Pins 12-22: 0,1,2,3,4,5,6,7,8,9, +VF.

    It has nothing marked as: DS, OE, LATCH, CLK;

    It’s the same as eBay’s: % 3DSOI.DEFAULT% 26a% 3D1% 26asc% 3D50546% 26meid% 3D958831e511d349638fb7ad0e41153449% 26pid% 3D100752% 26rk% 3D6% 26sd% 3D113004079683% 261% 3D112991529999 & _trksid = p2047675.c100752.m1982

    and already comes soldier in a pcb; I’d like to use your code but it certainly will not be possible. If you can help me, I thank you very much;

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